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a^2-8a-78=6
We move all terms to the left:
a^2-8a-78-(6)=0
We add all the numbers together, and all the variables
a^2-8a-84=0
a = 1; b = -8; c = -84;
Δ = b2-4ac
Δ = -82-4·1·(-84)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-20}{2*1}=\frac{-12}{2} =-6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+20}{2*1}=\frac{28}{2} =14 $
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